Author: | Wojciech Muła |
---|---|

Added on: | 2014-03-09 |

The description of Determine if a word has a zero byte from "Bit
Twiddling Hacks" says about `haszero(v)`: "*the result is the high
bits set where the bytes in v were zero*".

Unfortunately this is not true. The high bits are also set for ones followed
zeros, i.e. `haszero(0xff010100) = 0x00808080`. Of course the result
is still valid (non-zero if there were any zero byte), but if we want to
iterate over all zeros or find **the last** zero index, this could be a
problem.

It's possible to create the exact mask:

uint32_t nonzeromask(const uint32_t v) { // MSB are set if any of 7 lowest bits are set const uint32_t nonzero_7bit = (v & 0x7f7f7f7f) + 0x7f7f7f7f; return (v | nonzero_7bit) & 0x80808080; } uint32_t zeromask(const uint32_t v) { // negate MSBs return (nonzeromask(v)) ^ 0x80808080; }

Function `nonzeromask` requires 4 simple instructions, and
`zeromask` one additional xor.